come in
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if n is not a power of 2, then there exists an odd prime dividing n, say p. then, n=pq.
then,
2^n+1=2^pq+1=(2^q+1)(2^(p-1)q-2^(p-2)q+...+2^2q-2^q+1)
and p is odd, LHS=RHS.
QED.
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