是这样的,2 A all have 3 AUs, 1 C has 1 AU, 1 C has 4 AUs, 1 C has 3 AUs, 2 B have 1 AUs, 1 B has 3 AUs. I am in NTU, 所以,是不是 (2*5*3+1*2*1+1*2*4+1*2*3+2*3.5*1+1*3.5*3)/(6+1+4+3+3+2) =63.5/19 =3.35 我从来没有考这么差过, 其实我原来的主课连B都很少拿, 这一次... 我都不知道该怎么办了. sigh