If the density function is fa(t) and fb(t) where 10 (more...)
Is it?
Suppose change the waiting time to 40 min and two person's arrival time follows uniform distribution, e.g.
f(x) = 1 (10 < x < 11)
f(y) = 1 (10 < y < 11)
Then you answer will be
\int_{10}^{11}\int_{y-2/3}^{y+2/3) 1 dx dy
= 4/3
??
f(x) = 1 (10 < x < 11)
f(y) = 1 (10 < y < 11)
Then you answer will be
\int_{10}^{11}\int_{y-2/3}^{y+2/3) 1 dx dy
= 4/3
??
Yeah!
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