老兄你在乱猜是吧1D里面没有曲线。
the trajectory of each worm should be a whirling line. (my guess)
only A contribute to reducing distance between A,B.
so timeToMeet = 1/1 = 1 = 1/2 + 1/2 > PI/4.
hence the traveling trajectory sure break out the northwest cubicle of the big cube.
only a whirling curve meet that condition.
so timeToMeet = 1/1 = 1 = 1/2 + 1/2 > PI/4.
hence the traveling trajectory sure break out the northwest cubicle of the big cube.
only a whirling curve meet that condition.
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