if you know sth about stochastic, this is a stopping-time problemP(s_t = 2 ) = { (q/p)^0 - (q/p)^(-1/2) } / {(q/p)^2 - (q/p)^(-1/2) }
p = 2/3 ; q = 1/3;
answer is .8
what is the general formula for the stopping time?
Was my calculation wrong? Did I interpret your equation wrongly? The answer was 0.356 not 0.8 BTW, how about the winning probability of the second player? Thanks
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